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NECO SSCE Physics 2015 past questions and answers

This 2015 NECO SSCE Physics set has 40 practice questions. Try these 5 free sample questions, tap a question to reveal the answer and explanation. Then practise the whole 2015 set with instant marking.

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Sample NECO SSCE Physics 2015 questions

1. A transistor has a collector current of 12 mA and a base current of 0.20 mA; what is its current gain?
  1. 60
  2. 24
  3. 0.017
  4. 12.2

Answer: A. 60

The current gain is the collector current divided by the base current, so 12/0.20 = 60.

2. A single diode connected in series with a load and an alternating-current source produces an output that is best described as
  1. steady direct current
  2. pulsating direct current from one half-cycle
  3. alternating current of twice the frequency
  4. an unchanged alternating voltage across the load

Answer: B. pulsating direct current from one half-cycle

A single diode conducts during one half-cycle and blocks the other, giving half-wave pulsating direct current.

3. Light of a certain frequency shines on a clean metal surface, but no photoelectrons are emitted; which change alone can make emission possible if the frequency is below the metal's threshold frequency?
  1. Increase the illuminated area
  2. Increase the exposure time
  3. Raise the light frequency above the threshold
  4. Increase the distance of the source

Answer: C. Raise the light frequency above the threshold

Photoemission requires each photon to have at least the work-function energy, which occurs only at or above the threshold frequency.

4. When a nucleus emits an alpha particle, how do its mass number A and atomic number Z change?
  1. A decreases by 2 and Z decreases by 4
  2. A and Z each decrease by 1
  3. A is unchanged and Z decreases by 2
  4. A decreases by 4 and Z decreases by 2

Answer: D. A decreases by 4 and Z decreases by 2

An alpha particle contains two protons and two neutrons, so emission reduces A by 4 and Z by 2.

5. Which is the dimensional formula for pressure in terms of mass M, length L and time T?
  1. M L^-1 T^-2
  2. M L T^-2
  3. M L^-2 T^-1
  4. M^0 L^-1 T^-2

Answer: A. M L^-1 T^-2

Pressure is force per area, giving (M L T^-2)/L^2 = M L^-1 T^-2.

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