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NECO SSCE Chemistry 2006 past questions and answers

This 2006 NECO SSCE Chemistry set has 40 practice questions. Try these 5 free sample questions, tap a question to reveal the answer and explanation. Then practise the whole 2006 set with instant marking.

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Sample NECO SSCE Chemistry 2006 questions

1. For a reaction, doubling the concentration of a reactant makes the initial rate four times as large while other conditions remain constant; what is the order with respect to that reactant?
  1. Zero order
  2. Second order
  3. First order
  4. Third order

Answer: B. Second order

A doubling gives a rate factor of 2^n, so 2^n = 4 and n = 2.

2. What quantity of heat is absorbed when 50 g of water is heated from 20°C to 28°C, given that its specific heat capacity is 4.2 J g^-1 °C^-1?
  1. 1680 J
  2. 420 J
  3. 840 J
  4. 3360 J

Answer: A. 1680 J

Using q = mcΔT gives 50 × 4.2 × 8 = 1680 J.

3. A catalyst is added to a reversible reaction at equilibrium; what is its effect on the equilibrium mixture?
  1. It shifts equilibrium towards products
  2. It shifts equilibrium towards reactants
  3. It does not change the equilibrium composition
  4. It stops the reverse reaction

Answer: C. It does not change the equilibrium composition

A catalyst speeds both forward and reverse reactions equally and therefore does not alter the equilibrium composition.

4. Aqueous copper(II) sulfate is electrolysed using inert electrodes; which substances are formed at the cathode and anode respectively?
  1. Hydrogen and chlorine
  2. Copper and hydrogen
  3. Oxygen and copper
  4. Copper and oxygen

Answer: D. Copper and oxygen

Copper(II) ions are preferentially discharged at the cathode while water is oxidised to oxygen at the anode.

5. During electrolysis of concentrated aqueous sodium chloride with inert electrodes, which products are obtained at the cathode, anode and in solution respectively?
  1. Hydrogen, chlorine and sodium hydroxide
  2. Sodium, oxygen and sodium chloride
  3. Hydrogen, oxygen and hydrochloric acid
  4. Chlorine, hydrogen and sodium carbonate

Answer: A. Hydrogen, chlorine and sodium hydroxide

Water forms hydrogen at the cathode, chloride ions form chlorine at the anode, and sodium hydroxide remains in solution.

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