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JAMB UTME Chemistry 2005 past questions and answers

This 2005 JAMB UTME Chemistry set has 40 practice questions. Try these 5 free sample questions, tap a question to reveal the answer and explanation. Then practise the whole 2005 set with instant marking.

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Sample JAMB UTME Chemistry 2005 questions

1. A salt has solubilities of 20 g per 100 g of water at 20°C and 60 g per 100 g of water at 60°C. If 50 g of the salt is dissolved in 100 g of water at 60°C and the solution is cooled to 20°C, how much salt crystallizes out?
  1. 14 g
  2. 20 g
  3. 30 g
  4. 36 g

Answer: C. 30 g

At 20°C only 20 g remains dissolved, so 50 - 20 = 30 g crystallizes out.

2. What volume of 0.10 mol dm^-3 sodium hydroxide is needed to neutralize 25.0 cm^3 of 0.10 mol dm^-3 sulfuric acid?
  1. 50.0 cm^3
  2. 25.0 cm^3
  3. 12.5 cm^3
  4. 100.0 cm^3

Answer: A. 50.0 cm^3

The equation H2SO4 + 2NaOH -> Na2SO4 + 2H2O requires twice as many moles of NaOH, giving 50.0 cm^3.

3. During electrolysis of aqueous copper(II) sulfate using inert electrodes, which gas is normally released at the anode?
  1. Hydrogen
  2. Chlorine
  3. Sulfur dioxide
  4. Oxygen

Answer: D. Oxygen

At the inert anode, hydroxide ions or water are oxidized to produce oxygen.

4. In the change Fe2+ -> Fe3+ + e^-, what happens to the iron ion?
  1. It is reduced by gaining an electron
  2. It is oxidized by losing an electron
  3. It is neutralized by gaining a proton
  4. It is hydrolysed by losing a proton

Answer: B. It is oxidized by losing an electron

Oxidation is loss of electrons, and Fe2+ loses one electron to form Fe3+.

5. An ion contains 17 protons and 18 electrons; what is its charge?
  1. +2
  2. +1
  3. -1
  4. -2

Answer: C. -1

One more electron than proton gives the ion a net charge of -1.

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